1000: 送分题-A+B Problem
Memory Limit:256 MB
Time Limit:1.000 S
Judge Style:Normal Judger
Creator:
Submit:139
Solved:113
Description
Calculate a+b
Input
Two integer a,b (0<=a,b<=10)
Output
Output a+b
Sample Input Copy
1 2
Sample Output Copy
3
HINT
Q: Where are the input and the output? A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout. You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer". User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer" if you try to do so. Here is a sample solution for problem 1000 using C++/G++:
#include <iostream> using namespace std; int main() { int a,b; cin >> a >> b; cout << a+b << endl; return 0; }It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error. Here is a sample solution for problem 1000 using C/GCC:
#include <stdio.h> int main() { int a,b; scanf("%d %d",&a, &b); printf("%d\n",a+b); return 0; }Here is a sample solution for problem 1000 using PASCAL:
program p1000(Input,Output); var a,b:Integer; begin Readln(a,b); Writeln(a+b); end.Here is a sample solution for problem 1000 using JAVA: Now java compiler is jdk 1.5, next is program for 1000
import java.io.*; import java.util.*; public class Main { public static void main(String args[]) throws Exception { Scanner cin=new Scanner(System.in); int a=cin.nextInt(); int b=cin.nextInt(); System.out.println(a+b); } }Old program for jdk 1.4
import java.io.*; import java.util.*; public class Main { public static void main (String args[]) throws Exception { BufferedReader stdin = new BufferedReader( new InputStreamReader(System.in)); String line = stdin.readLine(); StringTokenizer st = new StringTokenizer(line); int a = Integer.parseInt(st.nextToken()); int b = Integer.parseInt(st.nextToken()); System.out.println(a+b); } }